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e30e61b789
Currently when the signal debug name transform sees something like `const foo = signal(0);`, it transforms the signal into `signal(0, {...(ngDevMode ? { debugName: 'foo' } : {})})`. After minification this becomes `signal(0, {})` which will allocate memory for the empty object literal.
These changes rework the logic to produce `signal(0, ...(ngDevMode ? [{ debugName: 'foo' }] : []))` which will be fully tree shaken away to `signal(0)`.
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| .. | ||
| compliance | ||
| ngtsc | ||
| BUILD.bazel | ||
| extract_i18n_spec.ts | ||
| mocks.ts | ||
| perform_compile_spec.ts | ||
| perform_watch_spec.ts | ||
| test_support.ts | ||
| typescript_support_spec.ts | ||
| version_helpers_spec.ts | ||